a 100g bullet is fired into 12kg block which is suspended by long cord. if the bullet is embedded in the block and the block rise by 5cm. what was the speed of the bullet?
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The ans is 1198cm
We will need to use the equation v^2-u^2=2as
And the momentum equilibrium equation
So , v = 12*9.81*5/12.1
=1198cm
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