Question

A 100kg block slides on the floor with an initial speed of 6.4m/s.if the cofficient of kinetic friction between the block and floor is 0.46,what is the player acceleration ? How far did he slide?​

Answer 1

Answer:

The maximum value of the static friction possible=μ

s

mg=0.5×100×10=500N>344N

Thus the static friction would adjust to 344N and would not allow the box to move at all.

Explanation:

The maximum value of the static friction possible=μ

s

mg=0.5×100×10=500N>344N

Thus the static friction would adjust to 344N and would not allow the box to move at all.

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