A 100kg block slides on the floor with an initial speed of 6.4m/s.if the cofficient of kinetic friction between the block and floor is 0.46,what is the player acceleration ? How far did he slide?
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Answer:
The maximum value of the static friction possible=μ
s
mg=0.5×100×10=500N>344N
Thus the static friction would adjust to 344N and would not allow the box to move at all.
Explanation:
The maximum value of the static friction possible=μ
s
mg=0.5×100×10=500N>344N
Thus the static friction would adjust to 344N and would not allow the box to move at all.
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