A 100kg man jumps into a swimming pool from a height of 5m. It takes 0.4 sec for the water to reduce his velocity to zero. What average force did the water exert on the man?
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If a 100 kg man jumps into a swimming pool from a height of 5.0 meters, and it takes 0.40 seconds for the water to reduce his velocity to zero, then the average force did the water exert on the man is -4.5 m/s. The formula is F = m (vf - vi)/t.
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Mass=100kg
A=5-0/0.4=12.5m/s
Force=ma=100×12.5=1250N
So the force is 1250N
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A=5-0/0.4=12.5m/s
Force=ma=100×12.5=1250N
So the force is 1250N
pls mark as brainliest
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