Math, asked by devamgarg556677, 3 months ago

A 100m race was organised in a school campus ground on sports meet. The

time was recorded with the help of a stopwatch.

A table shown below describes the time in which the race was finished.

Time

( in Secs)

0-20 20-40 40-60 60-80 80-100

No. Of

Student

6 13 10 3 8

a) What will be the lower limit of modal class?

i. 30 ii. 40 iii. 60 iv. 20

b) The average time taken by the student to finish the race is _____

i. 40 ii. 47 iii. 50 iv. 30

c) How many students finish the race within one minute?

i. 30 ii. 29 iii. 19 iv. 29

d) The construction of cumulative frequency table is useful to determine

i. Mean ii. Median iii. Mode iv. All of i, ii, iii.

e) How many students participated in 100 m race on sportsmeet.

i. 30 ii. 35 iii. 25 iv. 40​

Answers

Answered by Gaurav7256
0

Answer:

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Answered by amitnrw
2

Given : A stopwatch was used to  find the time that it took a  group of students to run 100  m.

Time  (in sec)  0-20 20-40 40-60 60-80 80-100

No. of  students   6     13      10          3           8

To Find :  lower limit of modal class?

i. 30 ii. 40 iii. 60 iv. 20

The average time taken by the student to finish the race

Solution:

Time  (in sec)    f               cf

0-20                6                6

20-40              13                19

40-60              10                29

60-80              3                32

80-100             8                40

modal class  = 20 - 40

Lower limit  = 20

average  time taken by a student to finish the race = (10*6 + 30*13+50*10+70*3+90*8)/40

= 47

students finish the race within one minute

1 minute = 60 sec

Time less than 60 sec  = 29 Students

29 students finished the race within 1 minute

The construction of cumulative frequency table is useful in determining the Median

40 s students participated in 100 m race on sportsmeet.

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