Physics, asked by mankarabhijeet, 17 days ago

A 100mH inductor, a 25μF capacitor and a 15Ω resistor are connected in series to a 120V, 50Hz ac source. Calculate current at resonance​

Answers

Answered by majeshk781
0

Explanation:

(a) Reason occurs when X

C

=X−L

∴z=15Ω

(b)I=

R

V

=

15

120

=8A

(c)X

C

=X

L

ω

C

1

L

ω

2

=

LC

1

ω=

LC

1

f=

LC

×

1

=100Hz

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