Question

A 100n force acts horizontally on a block of 10kg placed on a horizontal rough surface of coefficient of friction is 0.5 if the Acceleration due to gravity is taken as 10 meter per second square the acceleration of the block in meter per second square is​

Answer 1

$\huge\mathfrak\purple{ʕ•ᴥ•ʔAnswerʕ•ᴥ•ʔ}$

$\huge\bold{Here;}$

Mass - (M) = 10kg

Gravity - (g) = 10ms~²

Coefficient of Friction - (μ) = 0.5

Force - (F) = 100N

$\huge\bold{So;}$

Force of Friction

f = μN

f = μmg

f = 0.5 × 10kg × 10 ms~²

f = 50 N

$\huge\bold{Next;}$

Force the produce acceleration

F¹ = F¹ - f

F¹ = 100N - 50N

F¹ = 50N

$\huge\bold{Next;}$

Acceleration is ;

a = F¹ / m

a = 50N / 10kg

a = 5 ms~²

$\huge\mathfrak\red{ᴥ︎︎︎ Acceleration =5ms~²}$