Question

A 100N uniform rod of length 6L is supported by two forces F1 and F2 as shown here. What is the ratio for F1 and F2??​

Answer 1

Answer:

Explanation: For rotational equilibrium.

Moment of forces should be equal

Taking moment of force at the centre of rod

F1×2L =F2×L

Hence F1/F2 =1/2

Answer 2

Given,

Length of the uniform rod= 6L

The rod is supported by two forces F₁ and F₂

To find,

The ratio of the forces F₁ and F₂

Solution,

We can use the following procedure to solve this numerical question.

We know that,

The force F₁ is balanced at L distance from the end, while the force F₂ is balanced at a distance of 2L from the other end.

Now,

For the system to be in a stable state, the moments of forces must be equal.

Thus,

Balancing the moment of force on the midpoint of the rod.

⇒ F₁ × 2L = F₂ × L

⇒ $\frac{F1}{F2}$ = $\frac{1}{2}$

As a result, the ratio of the two forces F₁ and F₂ is 1:2.