Question

A 100V AC of frequency 50Hz is connected to a series L-C-R with L=8.1mH, C= 12.5 µF and R = 10 Ohm. find potential difference across resistance.
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Answer 1

Answer:

Impedance of series RLC circuit is given by:

Z=

R

2

+(2πfL−

2πfC

1

)

2

Z=

10

2

+(2π×500×8.1×10

−3

−

2π×500×12.5×10

−6

1

)

2

Z≈10 Ω

Current flowing through the circuit is:

I=

Z

V

=10A

Potential difference across the resistor, by ohm's Law is:

V

R

=IR=10×10=100 V