Question

a 100w bulb emits monochromatics light of A=400nm calculate the no. of photons emmited per sec. ​

Answer 1

answer : Energy of isolated photon is calculated by -

⇒E = hc/λ

⇒E = (6.63×10^-34 × 3×10^8) / (4×10^-7)

⇒E = 4.97×10^-19 J

No of photons emitted per unit time is calculated by -

⇒N = P / E

⇒N = 100 / (4.97×10^-19 J)

⇒N = 2×10^20 photons

Therefore, 2×10^20 photons are emitted

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