a 100w bulb emits monochromatics light of A=400nm calculate the no. of photons emmited per sec.
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answer : Energy of isolated photon is calculated by -
⇒E = hc/λ
⇒E = (6.63×10^-34 × 3×10^8) / (4×10^-7)
⇒E = 4.97×10^-19 J
No of photons emitted per unit time is calculated by -
⇒N = P / E
⇒N = 100 / (4.97×10^-19 J)
⇒N = 2×10^20 photons
Therefore, 2×10^20 photons are emitted
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