Question

A 100w electric bulb is lighted for 3hour daily and four 60w electric bulbs are lighted for two hour daily?Calculate the unit of energy consumed in the month of 30 days in September.

Answer 1

100 W = 100 joules per second

1 watt hour = 3600 joules .... (1)

The light bulb is lighted for two hours therefore,

100W × 2 hours = 200 watt hours

200 watt hours = 720000 joules .... ( using- 1)

1 KWh = 3600000 joules. .....(2)

Units consumed per day = 720000 ÷ 3600000

= 0.2 units .....(using- 2)

Units consumed in a month = 0.2 × 30 = 6units

Now,

Sum of power of four 40 watt bulbs = 160W

160watt × 4hours = 640 watt hours

640 watt hours = 2304000 joules ...(using 1)

Energy consumed per day =

2304000÷3600000 = 0.64 units ...(using- 2)

Energy consumed in a month = 0.64× 30 = 19.2

Total energy consumed in a month = 19.2 + 6

= 25.2 units

I hope this'll​ help you.

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