A 100W electric light bulb is connected to a 200V supply. Calculate (i) the current flowing in the bulb, and (ii) the resistance of the bulb
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Answered by
1
Answer:
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Answered by
7
Answer:
Rating of bulb is given as 220 V,100W i.e V
b
=200 V and P
b
=100 W
Thus resistance of bulb R=
P
b
V
b
2
=
100
(200)
2
=400 Ω
Equivalent resistance of 5 bulbs connected in series R
s
=5R=5×400=2000Ω
Supply voltage V
s
=200 V
So, current in the circuit I=
R
s
V
s
=
2000
200
=0.1 A
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