A 10cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 12 cm. The distance of the object from the lens is 18 cm. Find the nature position and size of the image formed
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Hii there,
● Answer -
Position => 36 cm
Size => 20 cm
Nature => maximized, real & inverted image
● Explanation -
# Given -
u = -18 cm
h1 = 10 cm
f = 12 cm
# Solution -
Using lens formula,
1/f = 1/v - 1/u
1/12 = 1/v - 1/-18
1/v = 1/12 - 1/18
v = 36 cm
Magnification by lens is calculated by -
M = -v/u = h2/h1
h2 = -h1 × v / u
h2 = -10 × 36 / (-18)
h2 = 20 cm
Therefore, real & inverted image of size 20 cm is formed 36 cm in front of convex lens.
Hope this helped...
● Answer -
Position => 36 cm
Size => 20 cm
Nature => maximized, real & inverted image
● Explanation -
# Given -
u = -18 cm
h1 = 10 cm
f = 12 cm
# Solution -
Using lens formula,
1/f = 1/v - 1/u
1/12 = 1/v - 1/-18
1/v = 1/12 - 1/18
v = 36 cm
Magnification by lens is calculated by -
M = -v/u = h2/h1
h2 = -h1 × v / u
h2 = -10 × 36 / (-18)
h2 = 20 cm
Therefore, real & inverted image of size 20 cm is formed 36 cm in front of convex lens.
Hope this helped...
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