Question

a 10g bullet fired from a 5kg gun leaves with the speed of 100 m/s. with what speed does the gun recoil.
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Answer 1

Answer:

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Explanation:

after firing the velocity of bullet (v)= 100 m/s, say the velocity of gun is V

mass of bullet (m)= 10/1000 kg , mass of gun (M)= 5 kg

From momentum conservation,

0= mv + MV

V = - (m/M)*v

V = - (10\5000)*100

V = -0.2 m/s (Negative sign indicates that velocity of gun and bullet is in opposite direction)

so the recoil velocity of the gun is 0.2 m/s