a 10g bullet moving at 200m/s stops after penetrating 5cm of wooden plank. the average force exerted on the bullet will be..
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Answered by
375
Given :
mass=10g=10/1000=0.01kg
Initial speed=u=200m/s
final velocity= o m/s
S=5cm=5/100=0.05m
From third equation of motion :V²-u²=2as
0²-(200)²=2ax0.05
-40000=ax5x2/100
-40000=a/10
a=-400000m/s²
From Newton's Second law:
F=ma
=0.01x(-400000)
=-4000N
∴ A force of 4000N acts in opposite direction.
mass=10g=10/1000=0.01kg
Initial speed=u=200m/s
final velocity= o m/s
S=5cm=5/100=0.05m
From third equation of motion :V²-u²=2as
0²-(200)²=2ax0.05
-40000=ax5x2/100
-40000=a/10
a=-400000m/s²
From Newton's Second law:
F=ma
=0.01x(-400000)
=-4000N
∴ A force of 4000N acts in opposite direction.
Answered by
24
Answer:
Given :
mass=10g=10/1000=0.01kg
Initial speed=u=200m/s
final velocity= o m/s
S=5cm=5/100=0.05m
From third equation of motion :V²-u²=2as
0²-(200)²=2ax0.05
-40000=ax5x2/100xplanation:
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