Physics, asked by srushti6, 1 year ago

a 10g bullet moving at 200m/s stops after penetrating 5cm of wooden plank the average force exerted on the bullet will be

Answers

Answered by Aaditya2003
22
V^2=u^2+2as
Therefore 0^2=40000+2*a*5/100(converting cm into m
Therefore-40000=a/10
=>a=-400000
F=ma
=10/1000kg*-400000
=-4000N

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