a 10g bullet travelling at 200m/s strikes and remains embedded in a 2kg target which is originally at rest but free to move. at what speed does the target move
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♻♻Here Is Your Answer♻♻
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➡Mass of Bullet=> 10g
➡Speed of Bullet=> 200m/s
➡Mass in which bullet embedded=> 2kg
Lets the Velocity of block "V"
Applying, Conservation of Mass
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10 (200) = (2000g) × V
=> V= 1m/s...Ans..✔
♻♻Here Is Your Answer♻♻
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
➡Mass of Bullet=> 10g
➡Speed of Bullet=> 200m/s
➡Mass in which bullet embedded=> 2kg
Lets the Velocity of block "V"
Applying, Conservation of Mass
-------------------------------------------------
10 (200) = (2000g) × V
=> V= 1m/s...Ans..✔
Answered by
3
Answer:
Explanation:
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
♻♻Here Is Your Answer♻♻
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
➡Mass of Bullet=> 10g
➡Speed of Bullet=> 200m/s
➡Mass in which bullet embedded=> 2kg
Lets the Velocity of block "V"
Applying, Conservation of Mass
-------------------------------------------------
10 (200) = (2000g) × V
=> V= 1m/s...Ans..
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