A 10gram of gas at 1 atm is cooled from 273°c to 0°c at constant volume. The pressure become 1/x. Find the value of x.
Answers
Answered by
1
Nhi ata kya karu haai re kya karu
Answered by
0
10 gram of gas
1 atm
cooled from 273°c to 0°c
constant volume
Pressure is 1/x
273°c = 1k
10 gram = 0.01 kg
therefore
X=(273×0.01)÷10
X=(2.73)÷10
X=0.273
Similar questions