Question

A 10kg ball A and B moving at a Speed of 8m/s collides with a 20 kg ball B initially at rest. After collision, the ball A and B move along direction making angles of 30° and 45° respectively with the initial direction of mass of A.Find the final Speed of the balls A and B.

Answer 1

Answer:

refer to the attachment......xd

Answer 2

The final velocity of the balls A and B are 5.85 m/s and 2.07 m/s.

Explanation:

Given that,

Mass of ball A = 10 kg

Mass of ball B = 20 kg

Speed of A = 8 m/s

The ball A and B move along direction making angles of 30° and 45° respectively with the initial direction of mass of A.

We need to calculate the final speed of the balls A and B

Using conservation of momentum

For x-axis,

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}$

Put the value into the formula

$10\times 8+0=10v_{1}\cos30+20v_{2}\cos45$

$80=5v_{1}\sqrt{3}+10v_{2}\sqrt{2}$...(I)

For y-axis,

$m_{1}v_{1}\sin\theta=m_{2}v_{2}\sin\phi$

Put the value into the formula

$10v_{1}\sin30=20v_{2}\sin45$

$5v_{1}=10v_{2}\sqrt{2}$....(II)

Form equation (I) and (II)

$v_{1}=5.85\ m/s$

$v_{2}=2.07\ m/s$

Hence, The final velocity of the balls A and B are 5.85 m/s and 2.07 m/s.

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Topic : collision

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