Question

A 10kg ball is dropped from a height of 10m. find a.the initial potential energy of the ball. b.the kinetic energy just before it reaches the ground. c.the speed just before it reaches the ground ​

Answer 1

given

mass of ball= 10kg

height = 10m

consider

g = 10m/s^2

we know that

that potential energy = mgh

On putting the value = 10*10*10= 1000j

We know that

kinetic energy= mv^2/2

from just above the earth the kinetic energy equals to potential energy.

so

Mv^2/2 = 1000

v = sqrt 2000/M

v = sqrt,200 m/s

Answer 2

Answer:

Here is your answer ll

Hope it helps you