A 10kg ball is dropped from a height of 10m. find the initial potential energy of the ball, the kintic energy just before it reaches the ground, and the speed just before the reaches the ground.
kdruvankarthik:
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Answers
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P. E =mgh
Here,
m=10 kg
H=10
g=9.8m/s
So
Mgh=10*10*9.8
P. E=980 joules
Just before k. E =980 joules
V=?
K. E-- 1/2mv²
980-- 1/2*10*v²
980*2/10--v²
1960/10--v²
196--v²
V--√196
V--14m/s
Here,
m=10 kg
H=10
g=9.8m/s
So
Mgh=10*10*9.8
P. E=980 joules
Just before k. E =980 joules
V=?
K. E-- 1/2mv²
980-- 1/2*10*v²
980*2/10--v²
1960/10--v²
196--v²
V--√196
V--14m/s
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