A 10kg ball is dropped from a height of 10m.find the speed just before it reaches the ground
Answers
Answered by
11
To Find :
- speed of ball just before it reaches the ground
Solution :
- mass of ball = 10kg
- height = 10m
- Acceleration due to gravity = 10m/s²
potential energy = mgh
= 10 × 10 × 10
= 1000 J
Kinetic energy = 1/2mv²
As we know that,
Initial potential energy = final kinetic energy
So,
⠀⠀⠀⠀⠀⇛ 1/2 × 10 × v² = 1000
⠀⠀⠀⠀⠀⇛ 5v² = 1000
⠀⠀⠀⠀⠀⇛ v² = 1000/5
⠀⠀⠀⠀⠀⇛ v² = 200
⠀⠀⠀⠀⠀⇛ v = √200
⠀⠀⠀⠀⠀⇛ v = 14.14
Hence
- Speed of ball just before it reaches the ground is 14.14m/s
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Answered by
123
Given :-
- A 10kg ball is dropped from a height of 10m.
To find :-
- Find the speed just before it reaches the ground.
Solution :-
- Mass of ball = 10kg
- Height = 10m.
- Acceleration due to gravity = 10m/s².
Potential energy = mgh
= 10 × 10 × 10
= 1000 J
Kinetic energy = 1/2mv²
As we know,
- Initial potential energy = final kinetic energy
So,
- 1/2 × 10 × v² = 1000
- 5v² = 1000
- v² = 1000/5
- v² = 200
- v = √200
- v = 14.14
Speed of ball just before it reaches the ground is 14.14m/s
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