Question

a 10kg ball is moving with 10m/s a work done on it increase it's speed 40m/s find work done

Answer 1

Answer:

Explanation:

Correct option is C)

Let their velocities after the collision be v

1

​

 

and v

2

​

. As we know for elastic collision.

Relative velocity of approach = relative velocity of separation

10−4=v

2

​

−v

1

​

⇒6=v

2

​

−v

1

​

⇒v

1

​

=v

2

​

−6

Applying conservation of momentum,

10×10+5×4=10v

1

​

+5v

2

​

120=10v

1

​

+5v

2

​

120=10(v

2

​

−6)+5v

2

​

=15v

2

​

−60

15v

2

​

=180⇒v

2

​

=12cm/sec

v

1

​

=6cm/sec