A 10kg ball moving with velocity of 10m/s collides with a 30 gm ball at rest on a smooth horizantle surface . Calculate the velocity of second ball if the first ball rebounds with a velocity of 5 m/s
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m1u1+m2u2=m1v1+m2v2
10×10+0.3×0=10×5+0.3×v2
100=50+0.3×v2
50/0.3=v2
-166.66m/s=v2
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10×10+0.3×0=10×5+0.3×v2
100=50+0.3×v2
50/0.3=v2
-166.66m/s=v2
Hope it'd helped
Pls mark as Brainliest
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