Question

A 10kg mass at rest explodes such that it splits into two parts such that the heavier part weighs 4 times the lighter one. If the heavier mass goes due west with velocity of 5 metres per second , find the velocity of the lighter part. Also specify the direction in which it goes.​

Answer 1

Answer:

Mass of one part m

1

=200 gm

Its velocity v

1

=12 m/s towards east

So, mass of other part m

2

=300−200=100 gm

Let its velocity be v

2

.

Applying conservation of linear momentum : P

f

−P

i

Or m

1

v

1

+m

2

v

2

=0

Or 200×12+100×v

1

=0

⟹ v

2

=−24 m/s

So, the second part will fly off towards west with a velocity of 24 m/s.

Explanation:

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