Question

a 10kg mass is suspended from a beam 1.2m long.the beam is fixed to a wall.find magnitude and direction (clockwise or anticlockwise) of resulting moment at point b

Answer 1

magnitude of moment of force=1.2x10 x10 N/m
                                                =120 N/m
If the beam is suspended from the right side of the direction then da resulting moment will beeventually  anticlockwise and If the beam is suspended from the left side then the  direction of resulting moment will be eventuall clockwise