Physics, asked by thangammayil, 1 year ago

a 10kg mass is suspended from a beam 1.2m long.the beam is fixed to a wall.find magnitude and direction (clockwise or anticlockwise) of resulting moment at point b

Answers

Answered by akashnilroy
12
Magnitude of moment of force = 1.2 x 10 x 10 N m = 120 Nm
If the beam is suspended from the right side, direction of resulting moment will be anticlockwise.
If the beam is suspended from the left side, direction of resulting moment will be clockwise.
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