Question

A 10kg monkey climbs up a massless rope that runs over a frictionless branch of a tree and back down to a 15kg package on the ground. the magnitude of the least acceleration the monkey must have if it is to lift the package off the ground is

Answer 1

Dear Student,

● Answer -

a = 4.9 m/s^2

● Explaination -

Minimum tension in spring required to lift package is -

T = m.g

T = 15×9.8

T = 147 N

Let a be minimum acceleration the monkey must have to lift the package.

F = T - W

Ma = T - Mg

a = T/M - g

a = 147/10 - 9.8

a = 14.7 - 9.8

a = 4.9 m/s^2

Hence, 4.9 m/s^2 is minimum acceleration the monkey must have to lift the package.

Thanks dear...

Answer 2

Answer:4.9 m/s²

Explanation:

If you get the answer then mark me brainliest