A 10kg object is dropped from a height and reached the ground in 10s, then its momentum at the
bottom will be
(a) 100 N-s
b. 1000 N
c. 1000 N-s
d. 100N
Answers
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Explanation:
p=mv
m=10kg
v= u+at
0+9.8*10
v=98m/s
p=mv
10kg*98m/s
980kgm/s
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