Chemistry, asked by suryaraoalapati, 8 months ago

A 10L cylinder has helium at 8 atm and
32°C. How many balloons of 2L each at
2 atm and 32° C can be filled with the
gas available from the cylinder​

Answers

Answered by Sakshi3090
3

Answer:

Since the equation is PV =RT, where P is pressure, V is volume, T is temperature and R is gas constant. This equation can be written as

PV/T = R = constant

This ratio applies to all pressure, volume, and temperature. So this equation can be expanded as

(P1 V1) / T1 =n*(P2V2)/T2 = R= Constant

Now Plug in values as V1 = 10 litres, P1 = 8 ATM, T1= 32 C , V2 = 2 liter, P2= 2ATM, T2= 32C

(8*10)/32 = n (2*2)/32

80/4 = n

20 = n

So 20 ballons can be filled using that gas.

Answered by yashe3110
5

Answer:

answer should be 15

Explanation:

The PV of balloon = 2 × 2 = 4 lit-atm

Gas from the cylinder is available to fill in the

balloons, until its pressure drops from 8atm to

2atm.

The PV of helium available = 10 × (8-2) = 60 lit-atm

Number of balloons filled=

PVof the gasavailable

PVof the balloon

=

60/4

= 15

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