A 10m long cable wire consists of 40 standards of steel. The cross section of each strand is 5 sq. mm. When this cable is used to lift a load of 4000N, how much extension can take place in the cable in mm? (Y= 2×10¹¹ N/m²)
Answers
Answer:
Extension = 0.2 mm
Explanation:
From the above question,
They have given :
Y= 2×10¹¹ N/m²
A 10m long cable wire consists of 40 standards of steel.
The cross section of each strand is 5 sq. mm. When this cable is used to lift a load of 4000N.
The extension in the cable can be calculated using the following formula:
To determine the area of the cable wire:
Area = 40x5 sq. mm = 200 sq. mm
Determine the Young's Modulus of the cable wire:
Young's Modulus = 2x10¹¹ N/m²
Calculate the extension of the cable wire:
Extension = Load/[Area x Young's Modulus]
Extension = 4000N/[200 sq.mm x 2x10¹¹ N/m²]
Extension = 0.2 mm
Extension = Load/[Area x Young's Modulus]
Extension = 4000N/[5 sq.mm x 2x10¹¹ N/m²]
Extension = 0.2 mm
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