Question

A 10m long ladder reached a window 8m high from the ground on placing it against a wall at a distance x. find the distance x.

Answer 1

Answer:

X = 6 metres.

Step-by-step explanation:

GIVEN :

AB = LENGTH OF LADDER = 10 M

AC = HEIGHT OF TOP MOST POINT FROM THE GROUND = 8 M

TO FIND :

VALUE OF X .

DISTANCE OF BASE OF LADDER FROM THE BASE OF WALL.

SOLUTION :

REFER TO THE DIAGRAM ABOVE

BY PYTHAGORAS THEOREM :

${x}^{2} = {10}^{2} - {8}^{2} \\ \\ { x= \sqrt{100 - 64} }^{} \\ \\ x = \sqrt{36} \\ \\ x = 6 \: metres.$

HENCE VALUE OF X IS 6 M.