Question

A = 10N, theta = 60°, B = 15N. Find | vector A + vector B | ?

Answer 1

Answer:

21.79 N

Explanation:

$|a + b| = \sqrt({ {a}^{2} + {b}^{2} } + 2ab \cos(60)) ) \\ = \sqrt{(100 + 225 + 2 \times 10 \times 15 \times \frac{1}{2} } \\ = \sqrt{475} = 21.79$