Question

a)10p+10=100. solve the problem by trial and error method​

Answer 1

Answer:

The answer is p=9

Step-by-step explanation:

By using trial and error method we input the value of 9 into the equation,

$10p+10=100\\10(9)=10=100\\90+10=100\\100=100$

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Answer 2

Given :

⬤ 10p + 10 = 100

To Find :

⬤ Value of P .

Solution :

• Let P = 1

$\bf{10(1) + 10 = 100}$

10 + 10 = 100

20 ≠ 100

No , P = 1 is not a Solution .

• Let P = 2

10(2) + 10 = 100

20 + 10 = 100

30 ≠ 100

Not , P = 2 is not a Solution.

• Let P = 3

10(3) + 10 = 100

30 + 10 = 100

40 ≠ 100

No , P = 3 is Not a Solution .

• Let P = 4

10(4) + 10 = 100

40 + 10 = 100

50 ≠ 100

No , P = 4 is Not a Solution .

• Let P = 5

10(5) + 10 = 100

50 + 10 = 100

60 ≠ 100

No , P = 5 is Not a Solution .

• Let P = 6

10(6) + 10 = 100

60 + 10 = 100

70 ≠ 100

No , P = 6 is not a Solution

• Let P = 7

10(7) + 10 = 100

70 + 10 = 100

80 ≠ 100

No , P = 7 is Not a Solution .

• Let P = 8

10(8) + 10 = 100

80 + 10 = 100

90 ≠ 100

No , P = 8 is Not a Solution .

• Let P = 9

10(9) + 10 = 100

90 + 10 = 100

100 = 100

So , P = 9 is a Solution .

Therefore , The Value of P is 9 .