Math, asked by raushansinha0837, 7 months ago

a( -11,7 ) and b ( -10, 6) are the points of the trisection of the line segment PQ .find the coordinate of p and q?​

Answers

Answered by amitnrw
0

Given : A( -11,7 ) and B ( -10, 6) are the points of the trisection of the line segment PQ

To Find : Coordinate of P and Q

Solution:

P               A               B           Q

(Px , Py)   (-11, 7)      (-10 , 6)     (Qx , Qy)

A( -11,7 ) and B ( -10, 6) are the points of the trisection of the line segment PQ

=> PA = AB = BQ  = PQ/3

PA = AB

=> A is mid point of  P & B

=>  - 11 = ( Px  - 10)/2 ,    7 = ( Py + 6)/2

=> -22 = Px - 10   ,   14 = Py + 6

=> Px = - 12     , Py  = 8

P = ( -12 , 8)

AB = BQ

B is mid point of A & Q

=> -10  = (-11 + Qx)/2  => -20 = -11 + Qx  => Qx  = -9

&  6 = ( 7 + Qy)/2 => 12 = 7 + Qy  => Qy = 5

Q = ( - 9 , 5)

P               A               B           Q

(-12 , 8)   (-11, 7)      (-10 , 6)     (-9 , 5)

P = ( -12 , 8)

Q = ( - 9 , 5)

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