Question

A/11+B/3=11/33 . Find A and B.​

Answer 1

Answer:

given A/11+B/3=11/33

Step-by-step explanation:

so,by LCM

3A+11B/33=11/33

divide both sides by 33 so that denominators get cancelled

so,3A+11B=11 [eq1]

suppose if B=0 then A=11/3

if B=1 then A=0

so values of A and B are 0, 1 respectively

check:- substitute values of A and B in [eq 1]

so,3(0)+11(1)=0+11=11 = RHS