Question

A
11. In the given figure, AB is a chord of a circle
with centre O and AB is produced to C such
that BC = OB. Also, CO is joined and produced
to meet the circle in D. IF ZACD = 25° then
LAOD = ?
(a) 50°
(b) 75
(c) 90°
(d) 100°​

Answer 1

Answer:

since BC= OB = radius of the circle angle boc=bco=25

angle oba= 25+25=50 =angle oab

then angle aob=180-(50+50)=80

therefore angle aod = aob+bod=aob+bco =

80 +25 =105

Answer 2

Answer:

b)75°

Please let me know if there are any mistakes.

Sorry my handwriting sucks