Math, asked by rajputjitin15, 1 day ago

a
11. Suppose a long metal wire girdles the equator and that the earth is girdled with a second wire
that has a 16 feet clearance from the ground. If the circumference of the earth at the equator
is 25,000 miles, how much longer will the second wire be compared to the first?
a. 32 feet
b. 100 feet
100 miles
d. 32 miles
C.

Answers

Answered by farhattabassum85
0

Answer to this question is

d. 32 miles

Answered by Syamkumarr
1

Answer:

The second wire is 32 feet (approx.) greater than the first wire.

Step-by-step explanation:

Given that the circumference of the Earth is 25000 miles.

Let the wire required to girdle the equator be 'x'

We know that the circumference is 2πr ; r being the radius

=> 2πr = 25000 = x

Now a second wire is girdled which is at a height 16 feet above the ground.

Therefore,

=> r = R +16

=> 2πR = 2π(r+16) = 2πr + 2π16 = x + 32π

Therefore, the second wire is longer than the first by = length of second wire - length of first wire

=> length = x + 32π - x

                = 32π

                ≈ 32

Therefore, the second wire is 32 feet (approx.) greater than the first wire.

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