A 110 m × 80 m rectangular plot has two crossroads, each 4m wide, running through its middle, one parallel to the length and the other parallel to the breadth. Find the area of the path and cost of cementing the roads at ₹15 per m².
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Answer:
Area of road: 744m²
Total cost of cement 11160
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Step-by-step explanation:
Rectangle: 110m by 80 m
Area of Road parrell to length: 110×4 = 440m²
Area of Road parrell to width: 80×4 = 320m²
Overlapping Area of road: 4×4 = 16m²
Total Area of road = (440m²+320m²) - ( overlapping area)
= 760m²- 16m²
Area of Road = 744 m²
Cost of cement : 15 per m²
Total cost of cement: 15× 744 = 11160
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