Math, asked by rasmitaporichha2005, 16 days ago

A С 110° In the figure, given alongside, AOB is a diameter of the circle and ZAOC = 110°. Find ZBDC. ​

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Answered by selfiequeen001
0

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Answer:

Standard Algebraic Identities List

Identity I: (a + b)2 = a2 + 2ab + b2

Identity III: a2 – b2= (a + b)(a – b)

Identity IV: (x + a)(x + b) = x2 + (a + b) x + ab.

Identity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca.

Identity VI: (a + b)3 = a3 + b3 + 3ab (a + b)

Step-by-step explanation:

Standard Algebraic Identities List

Identity I: (a + b)2 = a2 + 2ab + b2

Identity III: a2 – b2= (a + b)(a – b)

Identity IV: (x + a)(x + b) = x2 + (a + b) x + ab.

Identity V: (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca.

Identity VI: (a + b)3 = a3 + b3 + 3ab (a + b)

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