Question

A 112 cm long wire is bent to form a right-angled triangle with hypotenuse 50 cm. Find the area of the triangle so formed.

Answer 1

Answer:

Step-by-step explanation:

Let one of the perpendicular sides be A units.

Therefore the other side is B which is obtained as followes

A + B + 50 = 112

=> B = 112 - 50 - A = 62 - A units.

(As the perimeter of the triangle is the length of the wire.)

Also, since it is a right angle triangle, we must have

502 = A2 + B2

=> 2500 = A2 + (62 - A)2

=> 2500 = A2 + 3844 + A2 - 124A

=> 2A2 - 124A + 1344 = 0

=> A2 - 62A + 772 = 0

=> 62A - A2 = 772 (1)

Now, Area of the right triangle = 0.5 x A x B = 0.5 x A x (62 - A)

= 0.5 x (62A - A2)

= 0.5 x 772 (from 1)

= 386 sq units

I hope it will help u

Thank you

Answer 2

Answer:

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