A 112cm long wire is bent to form a right angled triangle with hypotenuse 50 cm .Find the area of the triangle so formed quadratic equation
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Perimeter of triangle = 112 cm
hypotenuse = 50 cm
sum of other two sides = 112-50= 62 cm
Let base be b and height will be (62-b)
Area = 1/2*b*h
= 1/2*b*(62-b)
= 31b - b^2 /2
hypotenuse = 50 cm
sum of other two sides = 112-50= 62 cm
Let base be b and height will be (62-b)
Area = 1/2*b*h
= 1/2*b*(62-b)
= 31b - b^2 /2
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