A 115m long and 64m broad lawn has two crossroad at right angles, one 2m wide, running parallel to it's length and the other 2.5m wide, running parallel to it's breath. Find the cost of the road at ₹ 4.60 per m rase power 2
Answers
Answer:
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Step-by-step explanation:
Length of a lawn(l) = 115m
Breadth of a lawn (b) = 64 m
Width of lengthwise road(PQ)= 2.5 m
Width of breadththwise road (AB)= 2 m.
Area of road( ABCD)= 115×2= 230 m²
Area of road( PQRS)= 64×2.5= 160 m²
Area of common path EFGH= 2× 2.5= 5 m²
Area of the roads= (Area of road ABCD+ Area of road PQRS) - Area of Road EFGH
Area of the roads= 230+160-5
Area of the roads= 390-5= 385 m²
Rate of gravel = ₹ 4.60 per m²
Cost of gravelling the roads= 385 × 4.60= 1771
Hence, the Cost of gravelling the roads = ₹1771
Answer:
Rs. 1771 will be the cost of the road.
Step-by-step explanation:
Find the attached diagram for hint.
Consider the path that runs parallel to its length
Length of the path = 115m
Breadth of the path = 2m
Therefore, area of the path = 115m * 2m
= 230m²
Consider the path that runs parallel to its breadth
Breadth of the path = 64m
Length of the path = 2.5m
Therefore, area of the path = 64m * 2.5m
= 160m²
The area where the two roads intersect is overlapped
Therefore, the area overlapped = 2m * 2.5m
= 5m²
Therefore the total area of the path = Area of horizontal path + Area of vertical path - The overlapped area =>
Area of the path = 230m² + 160m² - 5m²
= 390m² - 5m²
= 385m²
We need to find the cost of the road.
We know that Cost = Rate * Area
=> Cost = 4.60 * 385
=> = Rs. 1771
Therefore, Rs. 1771 will be the cost of the road.
