Question

A 116 2/3 m long
wire is put into equal pieces measuring 8 l/3 m each. How many such small pieces are there?​

Answer 1

Answer:

14 pieces

Step-by-step explanation:

It's given that the length of the wire is 116 2/3 = (116 × 3 + 2)/3 = 350/3 m

and it's divided in equal pieces each measuring 8 1/3 = (8×3+1)/3 = 25/3 m.

To find the number of pieces we divide the total length of wire by the lenght of a piece

So,

350/3 ÷ 25/3

= 350/3 × 3/25

= 350/25

= 14

Therefore, the wire is divided in 14 pieces.

Answer 2

Answer:

Step-by-step explanation:

Given,

A length of the wire long = l = 116 2/3 m = 350/3 m = 116.6 m

Each piece of the length of the wire = 8 1/3 m = 25/3 m = 8.3 m

Total small pieces are in the wire = Length of the wire / Each piece of the wire

= 116.6 m / 8.3 m

= 14.04 m