Question

A 117 1/3m long rope is at into equal places measuring 7 1/3m each. How many such small pieces are these

Answer 1

to calculate total pieces we hav eto divide 117 1/3 by 7 1/3
which is equal to 16(approx.)

Answer 2

$length \: of \: rope = 117 \frac{1}{3} m \\ length \: of \: each \: equal \: division = 7 \frac{1}{3} m \\ number \: of \: peices = 117 \frac{1}{3} \div 7 \frac{1}{3} \\ \frac{352}{3} \times \frac{3}{22} = \frac{352}{22} = 16 \: \\ number \: of \: pieces = 16 \: \\ \\ hope \: it \: helps)$