Question

A 12.5 mL portion of a solution is diluted to 500mL and its molarity is determined to be .125?
What is the molarity of the original solution?

Answer 1

Final answer: Molarity of original solution = 5 M

Given that: We are given 12.5 mL portion of a solution is diluted to 500 mL and its molarity is determined to be 0.125 M.

To find: We have to find molarity of the original solution.

Explanation:

• Volume of the solution after dilution = 500 mL = 0.5 L

        Molarity of the solution after dilution M = 0.125 M

        Molarity of the solution M  =  $\frac{Number of moles of solute}{Volume of solution in liters}$

        0.125 M = Number of moles of solute / 0.5 L

        Number of moles of solute = (0.125 * 0.5) = 0.0625 moles

• Volume of given original solution = 1.25 ml

        0.0625 moles of solute present in 12.5 ml of the given solution.

        Molarity of original solution  M =    $\frac{Number of moles of solute}{Volume of solution in liters}$

        Number of moles of solute = 0.0625 moles

        Volume of the solution in liters = 12.5 mL = 0.0125 L

        Molarity of the original solution = (0.0625) / (0.0125) = 5 M

• Hence the molarity of original solution M = 5 M

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