Question

a 12.5m long and 9m wide room is surrounded by a 2.50 metre wide gallery find the cost of fixing tiles in the gallery at rate of ₹ 100 for sq m

Answer 1

The attachment shows you the figure for better understanding.

length of the room=12.5m

breadth of the room=9m

surrounded by 2.50m gallery.

TO FIND THE TILES COST FIRST WE NEED TO FIND THE AREA OF THE GALLERY.

$area \: of \: gallery =(area \: of \: room + gallery \: measure) - \\ area \: of \: room$

Area of room + gallery= 12.5+5 9+5
=17.5 and 14

Area of rectangle= length× breadth
= 17.5×14
=245 SQ.m
Area of room = length ×breadth
= 12.5×9
=112.5 sq m

Area of gallery= 245 - 112.5
=132.5

Total money required for tiles = 100×132.5
=13,250

THEREFORE THE TOTAL COST OF TILES NEEDED FOR GALLERY IS RS.13250