Question

A 12,600 kg railroad car travels on a level frictionless track (ha!) with a constant speed of 18 m/s. A 5350 kg load, initially at rest, is dropped onto the car. What will be the car’s new speed?

Answer 1

Answer:

12.63 m/s would be the new speed of the car

Explanation:

According to the law of conservation of momentum the momentum before collision And momentum after collision will be the same

So,

m1×v1 =m2×v2

12600 ×18 = 17950 × v2

12.63m/s = v2