a=-12 , b=3, c=1
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Answer:
a÷(b÷c)
=(a÷b)÷(a÷c)
LHS=a÷(b+c)=
b+c
a
RHS=(a÷b)+(a÷c)=
b
a
+
c
a
=
bc
ac+ab
∴LHS
=RHS
a=12,b=1 and c=−2
LHS=a÷(b÷c)=12÷[1÷(−2)]
=12÷
−2
1
=12×
1
−2
=−24
RHS=(a÷b)+(a÷c)
=(12÷1)+[12÷(−2))
=12−6
=6
LHS/RHS
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