a 12 cm long pipe is placed perpendicular is peripheral exis of concave mirror of focal length 12 cm at the distance of 8 cm from it . find position nature and size of image
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Explanation:
Distance of object from mirror u=−8cm
Focal length f=12cm
We know for mirror,
f
1
=
v
1
+
u
1
12
1
=
v
1
+
−8
1
Distance of image from lens v=4.8cm
Magnification ratio m=−
u
v
=−
−8
4.8
=0.6
Height of object h=1.2cm
Height of the image h
i
=m×h=0.6×1.2=0.72cm
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