Question

A 12 kg mass rests on a frictionless floor. If a 50 N force acts on it,
a) what will its acceleration be?
b) how far will it slide in 3.0 s
c) how fast will it be moving after 3.0 seconds?

Answer 1

Answer:

a. 50÷12

=4.16

b.4.5x4.16

17.26

Answer 2

Explanation:

Given 12 kg mass rests on a friction less floor. If a 50 N force acts on it. a) what will its acceleration be?

b) how far will it slide in 3.0 s

c) how fast will it be moving after 3.0 seconds?

• Given mass = 12 kg, F = 50 N. We need to find the acceleration.
• So F = ma
•      50 = 12 a
• Or a = 50 / 12
• Or a = 25 / 6
• So a = 4.16 m / s^2
• Now we need to find the distance in 3.0 secs
• So S = ut + 1/2 at^2
•        = 0 + 1/2 x 25/6 x 9
•      = 25 x 9 / 12
•     S = 75 / 4 m
•   S = 18.75 m
• Now we need to find the speed.
•      V = u + at  
•          = 0 + 25 / 6 x 3
•      V = 25 / 2 m / s
•     V = 12.5 m / s

Reference link will be

https://brainly.in/question/11556081